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Application Masterclass 1

Uniformly Accelerated Motion

20 Curated MCQs from Recognition to NEET/JEE Main Level

UAM-01

A particle starts from rest and moves with a constant acceleration of 4 m/s². Its velocity after 5 s is

Correct Answer: C

Trigger

Velocity after given time

Formula

v = u + at

Execution

v = 0 + 4 × 5

v = 20 m/s
Trap: Using displacement formula instead of velocity formula.

UAM-02

A particle starts from rest and accelerates uniformly at 2 m/s². The distance travelled in 4 s is

Correct Answer: C

Trigger

Displacement after given time

Formula

s = ut + ½at²

Execution

s = 0 + ½(2)(4)²

s = 16 m
Trap: Using v = at and reporting velocity as distance.

UAM-03

A particle moving at 10 m/s reaches 30 m/s in 5 s under uniform acceleration. The acceleration is

Correct Answer: B

Trigger

Velocity change over time

Formula

a = (v − u)/t

Execution

a = (30 − 10)/5

a = 4 m/s²
Trap: Dividing velocity by time instead of velocity change by time.

UAM-04

A car moving at 20 m/s is uniformly retarded at 5 m/s². How long will it take to come to rest?

Correct Answer: C

Trigger

Comes to rest

Formula

v = u + at

Execution

0 = 20 − 5t

t = 4 s
Trap: Ignoring negative acceleration.

UAM-05

A particle moving at 20 m/s comes to rest after travelling 40 m. The retardation is

Correct Answer: B

Trigger

Time not given

Formula

v² = u² + 2as

Execution

0 = 20² + 2a(40)

a = −5 m/s²
Trap: Trying to use v = u + at when time is absent.

UAM-06

A car moving at 25 m/s is uniformly retarded at 5 m/s². The stopping distance is

Correct Answer: B

Trigger

Stopping distance

Formula

v² = u² + 2as

Execution

0 = 25² − 10s

625 = 10s

s = 62.5 m
Trap: Finding stopping time instead of stopping distance.

UAM-07

A car moving at 20 m/s must stop before reaching a wall 30 m ahead. The minimum retardation required is closest to

Correct Answer: C

Trigger

Can stop before obstacle?

Formula

v² = u² + 2as

Execution

0 = 20² + 2a(30)

0 = 400 + 60a

a = −6.67 m/s²
Trap: Accessibility question. Do not calculate stopping time. Check whether the required state can be reached.

UAM-08

A particle accelerates uniformly from 10 m/s to 20 m/s in 5 s. Its average velocity is

Correct Answer: B

Trigger

Average velocity in UAM

Formula

Average Velocity

= (u + v)/2

Execution

(10 + 20)/2

= 15 m/s
Trap: Using average speed formulas from non-uniform motion.

UAM-09

Two particles start simultaneously from rest with accelerations 2 m/s² and 4 m/s². After the same time interval, the ratio of their velocities is

Correct Answer: B

Trigger

Equal time comparison

Formula

v = at

Execution

2t : 4t

1 : 2
Trap: Squaring accelerations unnecessarily.

UAM-10

Two particles start from rest and move for the same time with accelerations a and 2a. The ratio of distances covered is

Correct Answer: B

Trigger

Equal time comparison

Formula

s = ½at²

Execution

½at² : at²

1 : 2
Trap: Using velocity ratio instead of displacement ratio.

UAM-11

A particle moves with constant acceleration. Given:

u = 10 m/s
a = 2 m/s²
s = 60 m

Its velocity after travelling 60 m is

Correct Answer: C

Trigger

Time is absent.

Formula

v² = u² + 2as

Execution

v² = 10² + 2(2)(60)

v² = 340

v ≈ 18.44 m/s
Physics Check: The calculated answer is 18.44 m/s. None of the given options exactly match. Question or options should be corrected before publishing.

UAM-12

A particle reaches 25 m/s after accelerating at 3 m/s² for 5 s. Its initial velocity is

Correct Answer: B

Formula

v = u + at

Execution

25 = u + 3(5)

25 = u + 15

u = 10 m/s
Trap: Wrong sign while rearranging.

UAM-13

A particle moving at 10 m/s accelerates at 2 m/s². Can it attain 25 m/s after travelling 50 m?

Correct Answer: A

Trigger

Accessibility Question

Formula

v² = u² + 2as

Execution

v² = 10² + 2(2)(50)

v² = 300

v = 17.32 m/s
Physics Check: This calculation shows the particle cannot reach 25 m/s. Correct answer should actually be: B. No Question key must be corrected before publishing.

UAM-14

A particle moves with

u = 20 m/s
a = −5 m/s²

The time at which it changes direction is

Correct Answer: B

Key Idea

At turning point

v = 0

Execution

0 = 20 − 5t

t = 4 s
Trap: Students often use displacement formulas. Direction change occurs when velocity becomes zero.

UAM-15

A particle starts from rest with acceleration 2 m/s². Distance covered during the 5th second is

Correct Answer: C

Formula

Distance in nth second

sₙ = u + (a/2)(2n−1)

Execution

s₅ = 0 + (2/2)(9)

s₅ = 9 m
Trap: Students often calculate total displacement after 5 seconds instead of distance during the 5th second.

UAM-16

Two particles start simultaneously from rest. Their accelerations are:

2 m/s² and 8 m/s².

The ratio of distances covered after the same time interval is

Correct Answer: C

Formula

s = ½at²

Execution

½(2)t² : ½(8)t²

1 : 4
Trap: For equal time intervals, displacement ratio equals acceleration ratio.

UAM-17

A particle accelerates uniformly from 6 m/s to 18 m/s. Its average velocity is

Correct Answer: B

Formula

Average Velocity

= (u + v)/2

Execution

(6 + 18)/2

= 12 m/s
Trap: Do not use arbitrary averaging methods.

UAM-18

A car moving at 15 m/s accelerates uniformly at 2 m/s². The minimum distance required to reach 25 m/s is

Correct Answer: C

Formula

v² = u² + 2as

Execution

25² = 15² + 4s

625 = 225 + 4s

400 = 4s

s = 100 m
Trap: Accessibility problems are usually solved without finding time.

UAM-19

A particle has

u = −10 m/s
a = +2 m/s²

The time required to come momentarily to rest is

Correct Answer: C

Key Idea

At turning point

v = 0

Execution

0 = −10 + 2t

2t = 10

t = 5 s
Trap: Sign convention mistakes are common. Keep the signs throughout the calculation.

UAM-20

A particle starts from rest and travels 100 m in 10 s with constant acceleration. The acceleration is

Correct Answer: B

Formula

s = ut + ½at²

Execution

100 = 0 + ½a(10²)

100 = 50a

a = 2 m/s²
Trap: Starting from rest means u = 0.

Continue Learning

Move to the next application layer.

Vertical Motion

Free fall, upward projection and gravity-based motion.

Relative Motion

Observer frames and relative velocity.

Pursuit Problems

Catch-up situations and interception logic.

PYQ Masterclass

Exam-level applications and mixed concepts.